1264. 动态求连续区间和(树状数组模板题)

题目链接:

https://www.acwing.com/problem/content/description/1266/

题解:

模板题,记query()、add()、lowbit()函数即可

AC代码:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;

const int N = 1e5+5;

int a[N];
int tr[N];

int n,m;
int k,x,y;

int lowbit(int x){
    return x&-x;
}

int add(int x,int v){
    for(int i = x;i<=n;i+=lowbit(i)) tr[i] += v;
}


int query(int x){
    int sum = 0;
    for(int i=x;i>0;i-=lowbit(i)) sum+=tr[i]; 
    return sum;
}


int main(){
    scanf("%d%d",&n,&m);
    for(int i=1;i<=n;i++) scanf("%d",&a[i]);
    for(int i=1;i<=n;i++) add(i,a[i]);
    
    while(m--){
        scanf("%d%d%d",&k,&x,&y);
        if(k == 1) add(x,y);
        else{
            printf("%d\n",query(y) - query(x-1));
        }
    }
    
    
    return 0;
}

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转载自www.cnblogs.com/doubest/p/12315749.html