C++第11课--新型的类型转换

本文学习自 狄泰软件学院 唐佐林老师的 C++课程

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实验1：新型类型转换实例

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函数指针类型

实验1：新型类型转换实例

#include <stdio.h>

void static_cast_demo()
{
    int i = 0x12345;
    char c = 'c';
    int* pi = &i;
    char* pc = &c;
    
    c = static_cast<char>(i);
    pc = static_cast<char*>(pi);//error, static_cast<> 不能用于基本类型指针之间的类型转换
}

void const_cast_demo()
{
    const int& j = 1;
    int& k = const_cast<int&>(j);
    
    const int x = 2;
    int& y = const_cast<int&>(x);
    
    int z = const_cast<int>(x);// error  const_cast<>强制转换的目标必须是指针或引用
    
    k = 5;
    
    printf("k = %d\n", k);
    printf("j = %d\n", j);
    
    y = 8;
    
    printf("x = %d\n", x);
    printf("y = %d\n", y);
    printf("&x = %p\n", &x);
    printf("&y = %p\n", &y);
}

void reinterpret_cast_demo()
{
    int i = 0;
    char c = 'c';
    int* pi = &i;
    char* pc = &c;
    
    pc = reinterpret_cast<char*>(pi);
    pi = reinterpret_cast<int*>(pc);
    pi = reinterpret_cast<int*>(i);
    c = reinterpret_cast<char>(i); //error  只能用于指针和整数类型之间的强制类型转换
}

void dynamic_cast_demo()
{
    int i = 0;
    int* pi = &i;
    char* pc = dynamic_cast<char*>(pi);// error
}

int main()
{
    static_cast_demo();
    const_cast_demo();
    reinterpret_cast_demo();
    dynamic_cast_demo();
    
    return 0;
}