链地址法处理hash冲突建立Hash表代码练习

给定一个数组x[] = {4, 1, 3, 7, 8, 22, 45, 75}, 哈希函数为H(key) = key*2 % 11,采用链地址法处理哈希冲突。建立哈希表:

#include <bits/stdc++.h>
using namespace std;
const int maxsize = 11;

//哈希函数
int hash(int x) {return x*2 % maxsize;}

struct node {
	int val;
	node *next;
	
	node() {}
	node(int x, node *next) {
		this->val = x;
		this->next = next;
	}
};

node hashtable[maxsize];

int x[] = {4, 1, 3, 7, 8, 22, 45, 75};
void chain() {
	for (int i=0; i<maxsize; ++i) hashtable[i].next  = NULL;
	int n = sizeof(x) / sizeof(int);
	for (int i=0; i<n; ++i) {
		int addr = hash(x[i]);
		auto p = new node(x[i], hashtable[addr].next);
		hashtable[addr].next = p;
	}
}
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转载自blog.csdn.net/ASJBFJSB/article/details/103005356