Python算法 | 顺序搜索

def sequence_search(arr, target):
    for i in range(len(arr)):
        if target == arr[i]:
            return i # 返回target的索引
    return None # 找不到则返回None

arr = [99,12,33,74,521,13,14]
target = 521
print(sequence_search(arr, target)) # 4
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转载自blog.csdn.net/shaotianyang12/article/details/103398790