从列表的第一个数开始,顺序查找,如果与目标值相同,则返回索引,不同则返回None
代码如下:
def sequential_search(sequence, target):
for i in range(len(sequence)):
if target == sequence[i]:
return i
return None
def main():
x = [1, 5, 3, 7, 9]
print(sequential_search(x, 3))
print(sequential_search(x, 10))
if __name__ == '__main__':
main()
输出:
2
None