leetcode 两个链表相交的一系列问题

在这里插入图片描述

public class code_14_FindFirstIntersectNode{
	public static class Node{
		public int value;
		public Node next;
		
		public Node(int data){
			this.value=data;
		}
	}
	


	public static getIntersectNode(Node head1,Node head2){
		if(head1==null||head2==null){
			return null;
		}
		
		Node loop1=getLoopNode(head1);
		Node loop2=getLoopNode(head2);
		if(loop1!=null&&loop2!=null){
			return bothLoop(head1,loop1,head2,loop2);
		}
		return null;
	}
		
		
		//不用hash表返回入环中第一个节点
	public static getLoopNode(Node head){
		if(head==null||head.next==null||head.next.next==null){
			return null;
		}
		Node n1=head.next;//n1->slow
		Node n2=head.next.next;//n2->fast
		
		while(n1!=n2){
			if(n2.next==null||n2.next.next==null){
				return null;//快指针到结尾了,返回为空,不可能有环
			}
			n2=n2.next.next;
			n1=n1.next;
	}
			//当他们相同的时候跳出来,一步步走
        n2=head;
		while(n1!=n2){
			n1=n1.next;
			n2=n2.next;
		}
		return n1;//再次相同的点就是初始的结点
		
	}
	
	public static Node noLoop(Node head1, Node head2) {
		if (head1 == null || head2 == null) {
			return null;
		}
		Node cur1 = head1;
		Node cur2 = head2;
		int n = 0;
		while (cur1.next != null) {
			n++;
			cur1 = cur1.next;
		}
		while (cur2.next != null) {
			n--;
			cur2 = cur2.next;
		}
		if (cur1 != cur2) {
			return null;
		}
		cur1 = n > 0 ? head1 : head2;
		cur2 = cur1 == head1 ? head2 : head1;
		n = Math.abs(n);
		while (n != 0) {
			n--;
			cur1 = cur1.next;
		}
		while (cur1 != cur2) {
			cur1 = cur1.next;
			cur2 = cur2.next;
		}
		return cur1;
	}
	
	
    //两个有环链表相交
	public static Node bothLoop(Node head1, Node loop1, Node head2, Node loop2) {
		Node cur1 = null;
		Node cur2 = null;
		//java中只是一个标记  loop是汇编中的循环关键字
		if (loop1 == loop2) {
			cur1 = head1;
			cur2 = head2;
			int n = 0;
			while (cur1 != loop1) {
				n++;
				cur1 = cur1.next;
			}
			while (cur2 != loop2) {
				n--;
				cur2 = cur2.next;
			}
			cur1 = n > 0 ? head1 : head2;
			cur2 = cur1 == head1 ? head2 : head1;
			n = Math.abs(n);
			while (n != 0) {
				n--;
				cur1 = cur1.next;
			}
			while (cur1 != cur2) {
				cur1 = cur1.next;
				cur2 = cur2.next;
			}
			return cur1;
		} else {
			cur1 = loop1.next;//loop1在转,看是否相交

			while (cur1 != loop1) {
				if (cur1 == loop2) {
					return loop1;
				}
				cur1 = cur1.next;
			}
			return null;
		}
	}

	public static void main(String[] args) {
		// 1->2->3->4->5->6->7->null
		Node head1 = new Node(1);
		head1.next = new Node(2);
		head1.next.next = new Node(3);
		head1.next.next.next = new Node(4);
		head1.next.next.next.next = new Node(5);
		head1.next.next.next.next.next = new Node(6);
		head1.next.next.next.next.next.next = new Node(7);

		// 0->9->8->6->7->null
		Node head2 = new Node(0);
		head2.next = new Node(9);
		head2.next.next = new Node(8);
		head2.next.next.next = head1.next.next.next.next.next; // 8->6
		System.out.println(getIntersectNode(head1, head2).value);

		// 1->2->3->4->5->6->7->4...
		head1 = new Node(1);
		head1.next = new Node(2);
		head1.next.next = new Node(3);
		head1.next.next.next = new Node(4);
		head1.next.next.next.next = new Node(5);
		head1.next.next.next.next.next = new Node(6);
		head1.next.next.next.next.next.next = new Node(7);
		head1.next.next.next.next.next.next = head1.next.next.next; // 7->4

		// 0->9->8->2...
		head2 = new Node(0);
		head2.next = new Node(9);
		head2.next.next = new Node(8);
		head2.next.next.next = head1.next; // 8->2
		System.out.println(getIntersectNode(head1, head2).value);

		// 0->9->8->6->4->5->6..
		head2 = new Node(0);
		head2.next = new Node(9);
		head2.next.next = new Node(8);
		head2.next.next.next = head1.next.next.next.next.next; // 8->6
		System.out.println(getIntersectNode(head1, head2).value);

	}

}
	
			

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