c语言进行复数的四则运算

c语言进行复数的四则运算

额。。好像没什么好说的直接上代码吧,注意下结构体的用法

#include<stdio.h>
struct complex
{
	double re;
	double im;
};

complex add(complex x,complex y);
complex sub(complex x,complex y);
complex mul(complex x,complex y);
complex div(complex x,complex y);

	int main()
	{
		complex x={2,1},y={1,-3},z;
		z=div(x,y);
		printf("%lf+%lfi",z.re,z.im);
		return 0;
	}
	
complex add(complex x,complex y)
{
	complex z;
	z.re =x.re +y.re ;
	z.im =x.im +y.im ;
	return z;
}
complex sub(complex x,complex y)
{
	complex z;
	z.re =x.re -y.re ;
	z.im =x.im -y.im ;
	return z;
}
complex mul(complex x,complex y)
{
	complex z;
	z.re =(x.re *y.re)-(x.im *y.im ) ;
	z.im =(x.re *y.im)+(x.im *y.re ) ;
	return z;
}
complex div(complex x,complex y)
{
	complex z;
	double z0=y.re*y.re+y.im *y.im;
	z.re =((x.re *y.re)+(x.im *y.im))/z0;
	z.im =((x.re *y.im)-(x.im *y.re))/z0;
	return z;
}
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