最后习题
答案
\[ \begin{equation} \nonumber V = \left[ \begin{matrix} 2 & 2 \\ 1 + \sqrt{5} & 1 - \sqrt{5} \\ \end{matrix} \right ], A = \left[ \begin{matrix} 0 & 1 \\ 1 & 1 \\ \end{matrix} \right ] \end{equation} \]
\[ \begin{equation} \nonumber A^n = V(V^{-1}AV)^nA^{-1} \end{equation} \]
\(A^{-1}\)是\(A\)的逆