P4782 【模板】2-SAT 问题(2-SAT)

就只是模板而已

代码:

#include <bits/stdc++.h>
//luogu P4782
using namespace std;
const int N=2e6+5;

int n,m,a,va,b,vb;
int dfn[N],low[N],timer=0;
stack<int> s;
bool vis[N];
vector<int> e[N];
int co[N],color=0;

void add(int x,int y)
{
    e[x].push_back(y);
}

void tarjan(int u)
{
    dfn[u]=low[u]=++timer;
    s.push(u);
    vis[u]=1;
    for(auto v:e[u])
    {
        if(!dfn[v])
            tarjan(v),
            low[u]=min(low[u],low[v]);
        else if(vis[v])
            low[u]=min(low[u],dfn[v]);
    }
    if(low[u]==dfn[u])
    {
        int v;
        color++;
        do
        {
            v=s.top();
            s.pop();
            vis[v]=0;
            co[v]=color;
        }
        while(u!=v);
    }
}

bool solve()
{
    for(int i=1;i<=2*n;++i)
        if(!dfn[i]) tarjan(i);
    for(int i=1;i<=n;++i)
        if(co[i]==co[i+n])
            return 0;
    return 1;
}

int main()
{
    scanf("%d%d",&n,&m);
    for(int i=1;i<=m;++i)
    {
        scanf("%d%d%d%d",&a,&va,&b,&vb);
        int nota=va^1,notb=vb^1;
        add(a+nota*n,b+vb*n);//not a and b
        add(b+notb*n,a+va*n);//not b and a
    }
    if(solve())
    {
        puts("POSSIBLE");
        for(int i=1;i<=n;++i)
            printf("%d ",co[i]>co[i+n]);
    }
    else puts("IMPOSSIBLE");
    return 0;
}

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转载自www.cnblogs.com/oneman233/p/11716873.html