soj#547 bzoj5046 分糖果游戏

分析

代码

#include<bits/stdc++.h>
using namespace std;
#define int long long
const int inf = 1e9+7;
int f[160][160],s[160],p[160],v[160];
signed main(){
    int n,m,i,j,k,A,B;
    scanf("%lld%lld%lld",&n,&A,&B);
    for(i=1;i<=n;i++)scanf("%lld%lld",&p[i],&v[i]);
    for(i=n;i>0;i--)s[i]=s[i+1]+v[i];
    for(i=0;i<=v[n];i++)f[n][i]=-inf;
    for(i=v[n]+1;i<=s[n];i++)f[n][i]=inf;
    for(i=n-1;i>0;i--)
      for(j=0;j<=s[i];j++){
          if(v[i]>=j)f[i][j]=-inf;
            else f[i][j]=-(f[i+1][s[i]-j+1]-1)-p[i];
            int res=max(1ll,f[i+1][j]+p[i]+1);
            if(j<=s[i+1]&&f[i][j]>res)f[i][j]=res;
      }
    int Ans;
    for(i=0;i<=s[1];i++)
      if(A-B>=f[1][i])Ans=i;
        else break;
    cout<<Ans<<' '<<s[1]-Ans<<endl;
    return 0;
}

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转载自www.cnblogs.com/yzxverygood/p/11247999.html
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