Spring Security入门应用(ssm+maven)

本文导航:

   1.spring security maven依赖 和 方法级权限控制注解(jsr250)的maven依赖

   2.spring-security.xml

   3.service部分

   4.dao部分

   5.表

1.maven依赖:

<dependencies>    
    <dependency>        
        <groupId>org.springframework.security</groupId>        
        <artifactId>spring-security-web</artifactId>       
        <version>5.0.1.RELEASE</version>    
    </dependency>    

    <dependency>        
        <groupId>org.springframework.security</groupId>        
        <artifactId>spring-security-config</artifactId>        
        <version>5.0.1.RELEASE</version>    
    </dependency> 

    方法级权限控制注解
    <dependency>
        <groupId>javax.annotation</groupId>
        <artifactId>jsr250-api</artifactId>
        <version>1.0</version>
    </dependency>
</dependencies>

2.配置文件spring-security.xml 所需的配置信息

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
	xmlns:security="http://www.springframework.org/schema/security"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://www.springframework.org/schema/beans          
    http://www.springframework.org/schema/beans/spring-beans.xsd          
    http://www.springframework.org/schema/security          
    http://www.springframework.org/schema/security/spring-security.xsd">

	<!-- 方法级别的拦截 -->
	<security:global-method-security jsr250-annotations="enabled"></security:global-method-security>
    <!-- 配置不拦截的资源 -->
    <security:http pattern="/login.jsp" security="none"/>
    <security:http pattern="/failer.jsp" security="none"/>
    <security:http pattern="/css/**" security="none"/>
    <security:http pattern="/img/**" security="none"/>
    <security:http pattern="/plugins/**" security="none"/>
    
    <!-- 
    	配置具体的规则 
    	auto-config="true"	不用自己编写登录的页面，框架提供默认登录页面
    	use-expressions="false"	是否使用SPEL表达式（没学习过）
    -->

	<!--
		 使用这个bean 就可以不用修改下面内容也可以使用表达式（<security:authentication>这个就是表达式）
		 access="hasAnyRole('ROLE_USER','ROLE_ADMIN')"就是这个表达式
		 然后在页面中就可以使用：功能是：在页面显示当前登录用户的用户名，
		 <security:authentication property="principal.username"></security:authentication>
		 然而我在jsp中使用的话需要在jsp头部加上：
		 <%@taglib prefix="security" uri="http://www.springframework.org/security/tags" %>
<aside class="main-sidebar">
	-->
	<bean id="webexpressionHandler" class="org.springframework.security.web.access.expression.DefaultWebSecurityExpressionHandler"/>
    <security:http auto-config="true" use-expressions="false">

    	<!-- 配置具体的拦截的规则 pattern="请求路径的规则" access="访问系统的人，必须有ROLE_USER的角色" -->
		<security:intercept-url pattern="/**" access="ROLE_USER,ROLE_ADMIN"/>
    	<!-- 定义跳转的具体的页面 -->
    	<security:form-login  
    		login-page="/login.jsp"
    		login-processing-url="/login.do"
    		default-target-url="/index.jsp"
    		authentication-failure-url="/failer.jsp"
    	/>
    	
    	<!-- 关闭跨域请求 -->
    	<security:csrf disabled="true"/>
    	
    	<!-- 退出 -->
    	<security:logout invalidate-session="true" logout-url="/logout.do" logout-success-url="/login.jsp" />
    	
    </security:http>
    
    <!-- 切换成数据库中的用户名和密码 -->
    <security:authentication-manager>
    	<security:authentication-provider user-service-ref="userService">
    		<!-- 配置加密的方式 -->
    		<security:password-encoder ref="passwordEncoder"/>
    	</security:authentication-provider>
    </security:authentication-manager>
    
    <!-- 配置加密类 -->
    <bean id="passwordEncoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder"/>
    
 </beans>  

3.seivice

平时我们写的业务是:html -> Controller -> service -> dao -> html , spring security没有了Controller这一层了,登录请求来了之后直接访问到service后面就一样

service里面要继承 UserDetailsService

import org.springframework.security.core.userdetails.UserDetailsService;

public interface IUserService extends UserDetailsService {
    
}

service实现方法

import com.qy.ssm.domain.Role;
import com.qy.ssm.domain.UserInfo;
import com.qy.ssm.service.IUserService;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.security.core.authority.SimpleGrantedAuthority;
import org.springframework.security.core.userdetails.User;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UsernameNotFoundException;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;

import java.util.ArrayList;
import java.util.List;

@SuppressWarnings("SpringJavaAutowiringInspection") //我的userDao自动注入的它监测不到,报红,但是运行不报错,就用注解忽略一下这个报红
@Service("userService")
@Transactional
public class UserServiceImpl implements IUserService {

    @Autowired
    private IUserDao userDao;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        UserInfo userInfo = null;   //UserInfo 是我的bean类封装用户信息
        try {
            userInfo = userDao.findByUsername(username);
        } catch (Exception e) {
            e.printStackTrace();
        }
        /**
        *  处理自己的用户对象封装成UserDetails
        *  
        *  1.下面有两个构造方法 都可以实现
        *  第二个构造方法有一个userInfo.getStatus(),他是判断当前用户是否启用,我这个0是没有启用1是启用了,没有启用就还是不能登录,这个值在我的dao步骤我的数据表面能看见 status
        *  2.重点getAuthority(userInfo.getRoles())这个方法里面放的是用户查询出来的角色 
        */
        /*User user=new User(userInfo.getUsername(),userInfo.getPassword(),getAuthority());*/
        User user = new User(userInfo.getUsername(), "{noop}" + userInfo.getPassword(),
                userInfo.getStatus() == 0 ? false : true, true, true, true, getAuthority(userInfo.getRoles()));
        return user;
    }
    //作用就是返回一个List集合，集合中装入的是角色描述
    public List<SimpleGrantedAuthority> getAuthority(List<Role> roles) {

        List<SimpleGrantedAuthority> list = new ArrayList<>();
        for (Role role : roles) {
            list.add(new SimpleGrantedAuthority("ROLE_" + role.getRoleName()));
        }
        return list;
    }
}

4.Dao 查询 users 表,并通过中间表查询 role 表该用户的所有权限

import com.qy.ssm.domain.UserInfo;
import org.apache.ibatis.annotations.Many;
import org.apache.ibatis.annotations.Result;
import org.apache.ibatis.annotations.Results;
import org.apache.ibatis.annotations.Select;

import java.util.List;

public interface IUserDao {

    @Select("select * from users where username=#{username}")
    @Results({
            @Result(id = true, property = "id", column = "id"),
            @Result(property = "username", column = "username"),
            @Result(property = "email", column = "email"),
            @Result(property = "password", column = "password"),
            @Result(property = "phoneNum", column = "phoneNum"),
            @Result(property = "status", column = "status"),
            @Result(property = "roles",column = "id",javaType = java.util.List.class,
                    many = @Many(select = "com.qy.ssm.dao.IRoleDao.findRoleByUserId"))
    })
    public UserInfo findByUsername(String username) throws Exception;
}

上图中many = @Many(select = "com.qy.ssm.dao.IRoleDao.findRoleByUserId")级联查询的代码

@Select("select * from role where id in (select roleId from users_role where userId=#{id})")
    @Results({
            @Result(id = true,property = "id" ,column = "id"),
            @Result(property = "roleName",column = "roleName"),
            @Result(property = "roleDesc",column = "roleDesc"),
            @Result(property = "permissions" , column = "id",javaType = java.util.List.class,
                    many = @Many(select = "com.qy.ssm.dao.IPermissionDao.findPermissionByRoleId")
            )
    })
    public List<Role> findRoleByUserId(String id) throws Exception;

上图中com.qy.ssm.dao.IPermissionDao.findPermissionByRoleId级联查询的代码

@Select("select * from permission where id in (select permissionId from role_permission where roleId=#{id})")
    public List<Permission> findPermissionByRoleId(String id) throws Exception;

5.需要的三张表 users  users-role  role