【数据结构】完全二叉树判定

pta题号 L3-010
判断一棵树是否是完全二叉树的思路
1>如果树为空,则直接返回错
2>如果树不为空:层序遍历二叉树
  2.1>如果一个结点左右孩子都不为空,则pop该节点,将其左右孩子入队列;
  2.1>如果遇到一个结点,左孩子为空,右孩子不为空,则该树一定不是完全二叉树;
  2.2>如果遇到一个结点,左孩子不为空,右孩子为空;或者左右孩子都为空;则该节点之后的队列中的结点都为叶子节点;该树才是完全二叉树,否则就不是完全二叉树;

import java.util.LinkedList;
import java.util.Queue;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        Tree tree = new Tree();
        for (int i = 0; i < n; i++) {
            int num = in.nextInt();
            Node node = new Node(num);
            tree.addNode(node);
        }
        System.out.println(tree.judge()?"\nYES":"\nNO");
    }

    static class Node {
        int val;
        Node root;
        Node left;
        Node right;

        public Node(int val) {
            this.val = val;
        }
    }

    static class Tree {
        Node root;

        public void addNode(Node node) {
            if (root == null) {
                root = node;
            } else {
                build(node, root);
            }
        }

        private void build(Node node, Node root) {
            if (node.val > root.val) {
                if (root.left == null) {
                    root.left = node;
                    node.root = root;
                }
                else
                    build(node, root.left);
            } else {
                if (root.right == null) {
                    root.right = node;
                    node.root = root;
                } else {
                    build(node, root.right);
                }
            }
        }

        public boolean judge() {
            Queue<Node> queue = new LinkedList<>();
            //2.2算法的条件
            boolean flag = false;
            boolean res = true;
            //控制空格的
            boolean first = false;
            if (root == null)
                res = false;
            queue.offer(root);
            while (!queue.isEmpty()) {
                Node cur = queue.poll();
                if (first) System.out.print(" ");
                first = true;
                System.out.print(cur.val);
                if (flag) {
                    if (cur.left!=null || cur.right!=null)
                        res = false;
                }
                if (cur.left != null && cur.right != null) {
                    queue.offer(cur.left);
                    queue.offer(cur.right);
                } else if (cur.left == null && cur.right != null) {
                    res = false;
                    queue.offer(cur.right);
                } else {
                    flag = true;
                    if (cur.left!=null) queue.offer(cur.left);
                }
            }
            return res;
        }
    }
}

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转载自blog.csdn.net/HuaLingPiaoXue/article/details/87991485