题目描述:
代码如下:
//1001
#include <stdio.h>
int main ( void )
{
int n, count = 0;
scanf( "%d", &n );
while( n != 1 ){
if( n % 2 == 0 )
n /= 2;
else
n = ( 3 * n + 1 ) / 2;
count++;
}
printf( "%d", count );
}
题目描述:
代码如下:
//1001
#include <stdio.h>
int main ( void )
{
int n, count = 0;
scanf( "%d", &n );
while( n != 1 ){
if( n % 2 == 0 )
n /= 2;
else
n = ( 3 * n + 1 ) / 2;
count++;
}
printf( "%d", count );
}