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Given an integer array nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
基于贪心算法
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int sum = 0;
int maxsum = INT_MIN;
for (int i = 0; i < nums.size(); i++) {
if (sum + nums[i] <= 0) {
if (maxsum < 0) //这里加个判断更快
maxsum = max(maxsum, nums[i]);
else
sum = 0;
}
else {
sum += nums[i];
maxsum = max(maxsum, sum);
}
}
return maxsum;
}
};