题目内容:
编写程序利用递归法实现如下所示n层嵌套平方根的计算:
递归函数原型:double Y(double x, int n);
程序运行结果示例1:
Please input x and n:16,1↙
Result=4.00
程序运行结果示例2:
Please input x and n:16,2↙
Result=4.47
程序运行结果示例3:
Please input x and n:16,3↙
Result=4.52
程序运行结果示例4:
Please input x and n:16,0↙
Result=0.00
输入提示信息:“Please input x and n:”
输入格式: “%lf,%d”
输出格式: “Result=%.2f\n”
注意:为避免出现格式错误,请直接拷贝粘贴上面给出的输入、输出提示信息和格式控制字符串!
时间限制:500ms内存限制:32000kb
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
double Y(double x, int n);
double Y(double x, int n)
{
if (n==0)
return 0;
else
return sqrt(x+Y(x,n-1));
}
int main()
{
double x;
int n;
printf("Please input x and n:");
scanf("%lf,%d",&x,&n);
printf("Result=%.2f\n",Y(x,n));
system("pause");
return 0;
}