Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of the
maximum positive product involving consecutive terms of S. If you cannot find a positive sequence,
you should consider 0 as the value of the maximum product.
Input
Each test case starts with 1 ≤ N ≤ 18, the number of elements in a sequence. Each element Si
is
an integer such that −10 ≤ Si ≤ 10. Next line will have N integers, representing the value of each
element in the sequence. There is a blank line after each test case. The input is terminated by end of
file (EOF).
Output
For each test case you must print the message: ‘Case #M: The maximum product is P.’, where
M is the number of the test case, starting from 1, and P is the value of the maximum product. After
each test case you must print a blank line.
Sample Input
3
2 4 -3
5
2 5 -1 2 -1
Sample Output
Case #1: The maximum product is 8.
Case #2: The maximum product is 20.
代码
#include<bits/stdc++.h>
using namespace std;
int arr[27];
int main()
{
//freopen("F:\\1234.txt","r",stdin);
//freopen("F:\\12345.txt","w",stdout);
int n;
int kase=0;
while(cin>>n)
{
for(int i=0;i<n;i++)
cin>>arr[i];
long long mx=0;
for(int i=0;i<n;i++)
{
long long sum1=arr[i];
mx=max(mx,sum1);
for(int j=i+1;j<n;j++)
{
sum1*=arr[j];
mx=max(mx,sum1);
}
}
kase++;
cout<<"Case #"<<kase<<": The maximum product is ";
if(mx==0)
cout<<0;
else
cout<<mx;
cout<<"."<<endl<<endl;
}
return 0;
}