【Codeforces 159B】Matchmaker

【链接】 我是链接,点我呀:)
【题意】


笔和笔盖
笔有颜色和直径
笔盖也有颜色和直径
笔盖和笔如果直径相等
那么称为good
如果笔盖和笔直径相等、颜色也相等,那么称为very good
问你怎样安排笔和笔盖才能让good最多的情况下very good也最多.

【题解】


将直径相同的笔和笔盖放在同一个arraylist里面
然后写个hash,将颜色相同的优先配对
剩下的没办法只能委屈配对成"good"

【代码】

import java.io.*;
import java.util.*;

public class Main {
    
    
    static InputReader in;
    static PrintWriter out;
        
    public static void main(String[] args) throws IOException{
        //InputStream ins = new FileInputStream("E:\\rush.txt");
        InputStream ins = System.in;
        in = new InputReader(ins);
        out = new PrintWriter(System.out);
        //code start from here
        new Task().solve(in, out);
        out.close();
    }
    
    static int N = 1000;
    static class Task{
        
        class Pair{
            int x,type;
            public Pair(int x,int type) {
                this.x = x;this.type = type;
            }
        }
        
        int n,m;
        ArrayList<Pair> g[] = new ArrayList[N+10];
        int cnt[] = new int[N+10];
        
        public void solve(InputReader in,PrintWriter out) {
            for (int i = 1;i <= N;i++) g[i] = new ArrayList<Pair>();
            n = in.nextInt();m = in.nextInt();
            for (int i = 1;i <= n;i++) {
                int x,y;
                x = in.nextInt();y = in.nextInt();
                g[y].add(new Pair(x,1));
            }
            for (int j = 1;j <= m;j++) {
                int x,y;
                x = in.nextInt();y = in.nextInt();
                g[y].add(new Pair(x,2));
            }
            long ans1 = 0,ans2 = 0;
            for (int i = 1;i <= N;i++) {
                for (int j = 1;j <= N;j++) cnt[j] = 0;
                int len = g[i].size();
                for (int j = 0;j < len;j++)
                {
                    Pair temp = g[i].get(j);
                    if (temp.type==1) {
                        cnt[temp.x]++;
                    }
                }
                long pair_beautiful = 0,pair_normal=0;
                for (int j = 0;j < len;j++)
                {
                    Pair temp = g[i].get(j);
                    if (temp.type==2) {
                        if (cnt[temp.x]>0) {
                            cnt[temp.x]--;
                            pair_beautiful++;
                        }else pair_normal++;
                    }
                }
                long temp1 = 0;
                for (int j = 1;j <= N;j++) {
                    temp1+=cnt[j];
                }
                pair_normal = Math.min(temp1, pair_normal);
                ans1+=pair_normal;ans2+=pair_beautiful;
            }
            out.println((ans1+ans2)+" "+ans2);
        }
    }

    

    static class InputReader{
        public BufferedReader br;
        public StringTokenizer tokenizer;
        
        public InputReader(InputStream ins) {
            br = new BufferedReader(new InputStreamReader(ins));
            tokenizer = null;
        }
        
        public String next(){
            while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                try {
                tokenizer = new StringTokenizer(br.readLine());
                }catch(IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(next());
        }
    }
}

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转载自www.cnblogs.com/AWCXV/p/10507026.html