python 数据结构与算法——树的遍历

1、广度优先遍历

2、深度优先遍历

先序遍历:把根放在最前面

中序遍历:把根放在中间

后序遍历:把根放在后面

# -*- coding: utf-8 -*-
"""
Created on Mon Feb 25 21:47:53 2019
树的添加
@author: Xavier
"""
class Node(object):
    def __init__(self,item):
        self.elem=item
        self.lchild=None
        self.rchild=None
class Tree(object):
    #二叉树
    def __init__(self):
        self.root=None
        
    def add(self,item):
        node=Node(item)
        if self.root is None:
            self.root=node
            return
        
        queue=[self.root]
        
        while queue:
            cur_node=queue.pop(0)
            if cur_node.lchild is None:
                cur_node.lchild=node
                return
            else:
                queue.append(cur_node.lchild)
            if cur_node.rchild is None:
                cur_node.rchild=node
                return
            else:
                queue.append(cur_node.rchild)
                
    def breadth_travel(self):
        """广度遍历"""
        if self.root is None:
            return
        queue=[self.root]
        while queue:
            cur_node=queue.pop(0)
            print(cur_node.elem,end=" ")
            if cur_node.lchild is not None:
                queue.append(cur_node.lchild)
            if cur_node.rchild is not None:
                queue.append(cur_node.rchild)
    
    def preorder(self,node):
        #先序遍历
        #每次使用递归的代码都很简单
        if node is None:
            return
        print(node.elem,end=" ")
        self.preorder(node.lchild)
        
        self.preorder(node.rchild)   
        
    def inorder(self,node):
        #中序遍历
        #每次使用递归的代码都很简单
        if node is None:
            return
        
        self.inorder(node.lchild)
        print(node.elem,end=" ")
        self.inorder(node.rchild)
    def postorder(self,node):
        #后序遍历
        #每次使用递归的代码都很简单
        if node is None:
            return
        self.postorder(node.lchild)
        self.postorder(node.rchild)
        print(node.elem,end=" ")
    
tree=Tree()
tree.add(0)
tree.add(1)
tree.add(2)   
tree.add(3)
tree.add(4)
tree.add(5)
tree.add(6)
tree.add(7)
tree.add(8)
tree.add(9)
tree.breadth_travel()
print("")
tree.preorder(tree.root)
print("")
tree.inorder(tree.root) 
print("")
tree.postorder(tree.root)      
        

运行结果

runfile('D:/learn_code/code/数据结构与算法python/binary_tree.py', wdir='D:/learn_code/code/数据结构与算法python')
0 1 2 3 4 5 6 7 8 9 
0 1 3 7 8 4 9 2 5 6 
7 3 8 1 9 4 0 5 2 6 
7 8 3 9 4 1 5 6 2 0 

二、二叉树由树遍历确定一棵树

只要包含中序遍历就可以写出来,需要两个

https://www.bilibili.com/video/av21540971/?p=44

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转载自blog.csdn.net/zuyuhuo6777/article/details/87949182