smith数

#include<iostream>
#include<string.h>
using namespace std;
//求每一位总和
int add(int m)
{
    int sum = 0;
    int bc = 0;
    int p, q = m;
    while (q > 0) {
        p = q % 10;
        sum += p;
        q = q / 10;
    }
    return sum;
}
//判断是否为smith
bool smith(int m) {
    int a[10000] = { 0 };
    int i = 2;
    int temp = m;
    int ac = 0;
    int sum = 0;
    while (i <= temp) {
        if (temp%i == 0) {
            a[ac] = i;
            ac++;
            temp /= i;
            i = 2;
        }
        else i++;
    }
    for (int i = 0; a[i]!=0; i++);
    if (i == 1) return false;
    else {
        for (int i = 0; a[i]!=0; i++)
        {
            a[i] = add(a[i]);
            sum += a[i];
        }
        int sum2 = add(m);
        //cout << "所有因数之和:" << sum << " 所有位数之和:" << sum2 << endl;
        if (sum == sum2)return true;
        else return false;
    }
}

int main()
{
    int n, i = 0;
    int a[100] = { 0 };
    while (cin >> n && n != 0) {
        a[i++] = n;
    }
        
    for (int i = 0; a[i] != 0; i++)
    {
        int m = a[i] + 1;
        for (int i =m;; i++) {
            if (smith(i)) {
                cout << i << endl;
                break;
            }
        }

    }
    return 0;
}