python——京东二面笔试题

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京东二面笔试题

1. 生成一个大文件ips.txt,要求1200行，
   每行随机为172.25.254.0/24段的ip;
2. 读取ips.txt文件统计这个文件中ip出现频率排前10的ip;

##自己的：
import random
f = open('ips.txt','w+')

for i in range(1200):
    f.write('172.25.254.' + str(random.randint(1,255))+'\n')

f.seek(0.0)   ##将指针指向0

s = {}

for i in f.readlines():
    if i in s:
        s[i] += 1
    else:
        s[i] = 1
sort_li = list(s.items())
sort = sorted(sort_li,key=lambda x:x[1])[-10:]
for i in sort[::-1]:
    print(i[0],end='')

f.close()

结果：
172.25.254.149
172.25.254.180
172.25.254.17
172.25.254.158
172.25.254.156
172.25.254.201
172.25.254.225
172.25.254.81
172.25.254.28
172.25.254.98 

• 老师的：

import random

def create_ip_file(filename):
    ip = ['172.25.254.' + str(i) for i in range(0,255)]
    with open(filename,'a+') as f:
        for count in range(1200):
            # print(random.sample(ip,1))    ##random.sample返回的是列表
            f.write(random.sample(ip,1)[0] + '\n')

create_ip_file('ips.txt')     ##调用函数，生成1200行

def sorted_by_ip(filename,count=10):
    ips_dict = dict()     ##创建一个空字典
    with open(filename) as f:
        for ip in f:
            if ip in ips_dict:
                ips_dict[ip] += 1
            else:
                ips_dict[ip] = 1
    sorted_ip = sorted(ips_dict.items(),key=lambda x:x[1],reverse=True)[:count]
    return sorted_ip

print(sorted_by_ip('ips.txt'))