Spark的shuffle算子

一、去重

def distinct()
def distinct(numPartitions: Int)

二、聚合

def reduceByKey(func: (V, V) => V, numPartitions: Int): RDD[(K, V)]
def reduceByKey(partitioner: Partitioner, func: (V, V) => V): RDD[(K, V)]
def groupBy[K](f: T => K, p: Partitioner):RDD[(K, Iterable[V])]
def groupByKey(partitioner: Partitioner):RDD[(K, Iterable[V])]
def aggregateByKey[U: ClassTag](zeroValue: U, partitioner: Partitioner): RDD[(K, U)]
def aggregateByKey[U: ClassTag](zeroValue: U, numPartitions: Int): RDD[(K, U)]
def combineByKey[C](createCombiner: V => C, mergeValue: (C, V) => C, mergeCombiners: (C, C) => C): RDD[(K, C)]
def combineByKey[C](createCombiner: V => C, mergeValue: (C, V) => C, mergeCombiners: (C, C) => C, numPartitions: Int): RDD[(K, C)]
def combineByKey[C](createCombiner: V => C, mergeValue: (C, V) => C, mergeCombiners: (C, C) =>

  三、排序

def sortByKey(ascending: Boolean = true, numPartitions: Int = self.partitions.length): RDD[(K, V)]
def sortBy[K](f: (T) => K, ascending: Boolean = true, numPartitions: Int = this.partitions.length

四、充分区

def coalesce(numPartitions: Int, shuffle: Boolean = false, partitionCoalescer: Option[PartitionCoalescer] = Option.empty)
def repartition(numPartitions: Int)(implicit ord: Ordering[T] = null)

五、集合或者表操作

def intersection(other: RDD[T]): RDD[T]
def intersection(other: RDD[T], partitioner: Partitioner)(implicit ord: Ordering[T] = null): RDD[T]
def intersection(other: RDD[T], numPartitions: Int): RDD[T]
def subtract(other: RDD[T], numPartitions: Int): RDD[T]
def subtract(other: RDD[T], p: Partitioner)(implicit ord: Ordering[T] = null): RDD[T]
def subtractByKey[W: ClassTag](other: RDD[(K, W)]): RDD[(K, V)]
def subtractByKey[W: ClassTag](other: RDD[(K, W)], numPartitions: Int): RDD[(K, V)]
def subtractByKey[W: ClassTag](other: RDD[(K, W)], p: Partitioner): RDD[(K, V)]
def join[W](other: RDD[(K, W)], partitioner: Partitioner): RDD[(K, (V, W))]
def join[W](other: RDD[(K, W)]): RDD[(K, (V, W))]
def join[W](other: RDD[(K, W)], numPartitions: Int): RDD[(K, (V, W))]
def leftOuterJoin[W](other: RDD[(K, W)]): RDD[(K, (V, Option[W]))]

 转自:https://kuncle.github.io/spark/2017/03/13/Spark%E7%9A%84shuffle%E7%AE%97%E5%AD%90.html

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转载自blog.csdn.net/gegeyanxin/article/details/85038525