ajax与django后台json数据的交互

1新建django项目名为json_ajax,应用名为app,在templates模板中新建ajax.html文件

ajax.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>ajax</title>
    {% load staticfiles %}
    <script type="text/javascript" src="{% static 'js/jquery-3.3.1.min.js' %}"></script>
</head>
<body>
<button id="send">发送</button>
<script>
    $("#send").click(function () {
        {#json数据#}
        var post_data={
            "name":"weihu",
        };

        $.ajax({
            url:"http://127.0.0.1:8000/ajax",
            type:"POST",
            {#发送json数据到服务器#}
            data:post_data,

            {#请求成功回调函数#}
            success:function (data) {
                alert(data)
                alert("请求成功")
            },
            {#请求失败回调函数#}
            error:function () {
                alert("服务器请求超时,请重试!")
            }

        });
    });
</script>
</body>
</html>

2.在settings配置文件中，注释

1	`# 'django.middleware.csrf.CsrfViewMiddleware',`

STATIC_URL = '/static/'

STATICFILES_DIRS = [
    os.path.join(BASE_DIR, 'static'),
]

3.在urls.py文件中，配置path路径

"""json_ajax URL Configuration

The `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/2.0/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  path('', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  path('', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.urls import include, path
    2. Add a URL to urlpatterns:  path('blog/', include('blog.urls'))
"""
from django.contrib import admin
from django.urls import path
from app import views


urlpatterns = [
    path('admin/', admin.site.urls),
    path('test',views.test),
    path('ajax',views.ajax),
]

4.在views.py中，实现逻辑代码

from django.shortcuts import render,HttpResponse
import json

def test(request):
    return render(request,'ajax.html')

def ajax(request):
    if request.method=="POST":
        name=request.POST.get('name')
        print("ok")
        status=1
        result="sucuss"
        return HttpResponse(json.dumps({
            "status":status,
            "result":result,
            "name":name
        }))

ajax与django后台json数据的交互

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