一道Python面试的几种解答思路

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[[1,2],[3,4],[5,6]]代码展开，得到[1,3,5]的奇数列表。

方法一： 常规思路

>>> L = [[1, 2], [3, 4], [5, 6]]
>>> T = []
>>> for items in L:
...     for item in items:
...         if item % 2 == 1:
...             T.append(item)
>>> T
[1, 3, 5]

方法二： 列表推导

>>> L = [[1, 2], [3, 4], [5, 6]]
>>> T = []
>>> [T.append(i) for items in L for i in items if i % 2]
[None, None, None]
>>> T
[1, 3, 5]

方法三： 正则表达

>>> import re
>>> L = [[1, 2], [3, 4], [5, 6]]
>>> re.findall(r"[1-9]\d*[13579]|[13579]", str(L))
['1', '3', '5']

方法四：其他思路

>>> L = [[1, 2], [3, 4], [5, 6]]
>>> filter(lambda x:x%2, sum(L, []))
[1, 3, 5]