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题目要求:
Time limit : 1000 ms
Memory : 32768 KB
题目原题:
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes
问题简述:
输入两个数字,两个数字之间以空格分开,计算两个数字相加的和除于86的余数是否为零,若是在下一行输出yes,否在下一行输出yes,且要求可以输入多组数据。
问题分析:
考虑利用while()来创造输入多组数据的条件。
Virtua Judge通过的代码为:
#include <iostream>
using namespace std;
int main()
{
int A, B;
while (scanf_s("%d%d", &A, &B)!=EOF)
{
if ((A + B) % 86 == 0)
{
printf("yes\n");
}
else
{
printf("no\n");
}
}
return 0;
}