PAT (Advanced Level) Practice 1079 Total Sales of Supply Chain (25 分)

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#include<cstdio>
#include<vector>
using namespace std;

const int N=1e5+5;

int amount[N];
vector<int> G[N];
double p,r,ans;

void dfs(int u,double val)
{
    int f=0;
    for(int i=0;i<G[u].size();i++)
    {
        int v=G[u][i];
        f=1;
        dfs(v,val*(1+r*0.01));
    }
    if(!f) ans+=amount[u]*val;
}

int main()
{
    int n;
    scanf("%d%lf%lf",&n,&p,&r);
    for(int i=0;i<n;i++)
    {
        int k;scanf("%d",&k);
        if(k==0) scanf("%d",&amount[i]);
        else
        {
            for(int j=0;j<k;j++)
            {
                int x;scanf("%d",&x);
                G[i].push_back(x);
            }
        }
    }
    ans=0;
    dfs(0,p);
    printf("%.1lf\n",ans);
    return 0;
}

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转载自blog.csdn.net/Nightmare_ak/article/details/84348311