求单向链表的是否有环及环入口

版权声明：本文为博主原创文章，未经博主允许不得转载。 https://blog.csdn.net/qq_25244495/article/details/83446581

参考博客：https://www.cnblogs.com/dancingrain/p/3405197.html

bool HasLoop(Node* root, Node* &Entry)
{
	if(!root) return false;

	bool bHasLoop = false;
	Entry = nullptr;
	Node* pFast,*pSlow;
	pSlow = pFast = root;

	while(pFast)//pFast->pNext当pFast为nullptr时会报错：无法计算表达式的值
	{
		pSlow = pSlow->pNext;
		if(!pFast->pNext)	return false;//pFast->pNext当pFast为nullptr时会报错：无法计算表达式的值
		pFast = pFast->pNext;
		if(!pFast->pNext)	return false;
		pFast = pFast->pNext;
		if(pSlow == pFast)	
		{	
			bHasLoop = true;
			break;
		}
	}
	if(!bHasLoop) return false;

	while(root != pSlow)
	{
		root = root->pNext;
		pSlow = pSlow ->pNext;
	}
	Entry = pSlow;

	return true;
}

测试主函数：

struct Node
{
	Node* pNext;
	int val;
	Node(int v)
	{
		val = v;
		pNext = nullptr;
	}
};

int main()
{
	Node *root = new Node(0);
	Node *curNode = root;
	Node *entrySet;
	for (int i=1;i<=98;i++)
	{
		curNode->pNext = new Node(i);	
		curNode = curNode->pNext;
		if(i == 98) entrySet = curNode;//标记环形链表入口
	}
	
	curNode->pNext = new Node(99);//一共100个节点，值为0-99
	curNode->pNext->pNext = entrySet;//构造环形链表

	Node* entryGot;
	bool bHasLoop = HasLoop(root,entryGot);

	if(bHasLoop)
		cout << entryGot->val << endl;
	system("pause");
	return 0;
}