poj1187

对网上的代码做了些优化。。题解的话到处都有。

#include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
typedef long long ll;
const ll mod = 11380;
ll dp[31][11][11][11];
int l1, l2, l3, d;
int main()
{
	scanf("%d%d%d%d", &l3, &l2, &l1, &d);
	for (int i = 0; i <= d; i++)
		dp[i][0][0][0] = 1;
	for (int i = 1; i <= d; i++)
	{
		for (int j = 0; j <= l1; j++)
		{
			for (int k = 0; k <= l2; k++)
			{
				for (int q = 0; q <= l3; q++)
				{
					if (j + k + q < i)
					{
						dp[i][j][k][q] = dp[i - 1][j][k][q];
						continue;
					}
					for (int t = 0; t <=j - 1; t++)
					{
						dp[i][j][k][q] +=(dp[i - 1][t][0][0] * dp[i][j - t - 1][k][q]);
					}
					for (int r = 0; r <=k - 1; r++)
					{
						for (int t = 0; t <= j; t++)
						{
							dp[i][j][k][q]+=(dp[i - 1][t][r][0] * dp[i][j - t][k - r - 1][q]);
							
						}
					}
					for (int s = 0; s <= q - 1; s++)
					{
						for (int r = 0; r <= k; r++)
						{
							for (int t = 0; t <= j; t++)
							{
								dp[i][j][k][q]+=dp[i - 1][t][r][s] * dp[i][j - t][k - r][q - s - 1];
							}
						}
					}
					dp[i][j][k][q] %= mod;
				}
			}
		}
     }
	if (d)
		printf("%d\n", ((dp[d][l1][l2][l3] - dp[d - 1][l1][l2][l3]) % mod + mod) % mod);
	else
		printf("%d\n", dp[d][l1][l2][l3]);

}

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转载自blog.csdn.net/guoshiyuan484/article/details/82735094
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