C++--ACM之杭电OJ--1395 2^x mod n = 1

#include<iostream>
using namespace std;
int main()
{
    int n;
    int x;
    int i;
    long long t; 
    int m;
    while(cin>>n)              //n与2必为互质!!!!!
    {
        t=1;
        m=n;
        x=0;
        if(n%2==0||n==1)
        {
            cout<<"2^? mod "<<n<<" = 1"<<endl;
        }
        else
        {
            for(i=1;;i++)
            {
                t=t*2%m;           //!!!!!余数乘2对n取余 
                if(t==1)
                {
                    x=i;
                    break;
                }
            }
            if(x)
            {
                cout<<"2^"<<x<<" mod "<<n<<" = 1"<<endl; 
           }
           else cout<<"2^? mod "<<n<<" = 1"<<endl;

        }
    }
    return 0;
}

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转载自blog.csdn.net/William_Sunrise/article/details/81635388
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