python：求整数num范围内的勾股数，并统计a,b,c三个元素互为质数的勾股数的数量

def gcd(m,n):    #  求两个数的最大公约数,若为1则互为质数,返回TRUE
    if n== 0:
        m,n = n,m
    while m !=0:
        m,n = n%m, m
    if n == 1:
        return True
    else:
        return False

def gou_number(num =10):
    N = [i for i in range(1,num+1)]
    M = [i*i for i in range(1,num+1)]
    n=0
    number = 0
    for i in M:
        for j in M[n:]:
            if i+j in M:
                a = N[M.index(i)]
                b = N[M.index(j)]
                c = N[M.index(i+j)]
                if gcd(a,b) and gcd(a,c) and gcd(b,c):  #  abc是否互为质数
                    number += 1
        n += 1
    return number
print(gou_number())