1009 Product of Polynomials (25 分)
This time, you are supposed to find A×B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:K
where K is the number of nonzero terms in the polynomial,
and
(i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that
,
.
Output Specification:
For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up to 1 decimal place.
Sample Input:
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output:
3 3 3.6 2 6.0 1 1.6
解析
这题要注意的是:多项式相乘后:有的项的系数可能为0.注意筛选。
多项式相乘:用双重循环相乘后,生成的多项式:可能指数不是按从大到小排序的。
比如说:
polynomial1
polynomial2
polynomial
无论用什么数据结构:都要注意这上面的两点哟。
Code:
#include<iostream>
#include<cstdio>
#include<vector>
#include<utility>
#include<algorithm>
using namespace std;
vector<pair<int, double>>::iterator _Find(vector<pair<int, double>>::iterator begin, vector<pair<int, double>>::iterator end,int val) {
while (begin != end) {
if (begin->first == val)
return begin;
begin++;
}
return end;
}
bool cmp(pair<int,double> p1,pair<int,double> p2) {
return p1.first > p2.first;
}
int main()
{
int N1, N2;
cin >> N1;
vector<pair<int, double>> po1(N1, make_pair(0, 0));
for (int i = 0; i < N1; i++)
cin >> po1[i].first >> po1[i].second;
cin >> N2;
vector<pair<int, double>> po2(N2, make_pair(0, 0));
for (int i = 0; i < N2; i++)
cin >> po2[i].first >> po2[i].second;
vector<pair<int, double>> po;
int exponents;
double coefficient;
for (int i = 0; i < N1; i++) {
for (int j = 0; j < N2; j++) {
exponents = po1[i].first + po2[j].first;
coefficient = po1[i].second*po2[j].second;
auto it = _Find(po.begin(), po.end(), exponents);
if (it == po.end())
po.push_back(make_pair(exponents, coefficient));
else
it->second += coefficient;
}
}
int len=0;
for (auto x : po)
if (x.second != 0)
len++;
sort(po.begin(),po.end(), cmp);
cout << len;
for (auto it = po.cbegin(); it != po.cend(); it++) {
if(it->second!=0)
printf(" %d %.1f", it->first, it->second);
}
}