012_note

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找出数组中重复的数,并按重复数排序

var arr = [1, 3, 5, 2, 4, 1, 1, 1, 2];
  var newarrs = [];
  var newarrel = [];
  for (let i = 0; i < arr.length; i++) {
    for (let j = 0; j < i; j++) {
      if (arr[i] == arr[j]) {  // 找出数组中重复的数字,新建两个数组,一个放数字,一个放对象信息
        if (newarrs.indexOf(arr[i]) == -1) {
          newarrs.push(arr[i]);
          var obj = {};
          obj.str = arr[i];
          obj.num = 1;
          newarrel.push(obj);
        }
      }
    }
  }
  console.log(newarrs)
  console.log(newarrel)
  var num11 = 0;
  for (var x = 0; x < newarrs.length; x++) {
    for (let i = 0; i < arr.length; i++) {
      if (newarrs[x] == arr[i]) {
        num11++;
      }
    }
    newarrel[x].num = num11;
    num11 = 0;
  }
  console.log(newarrel)
  // newarrel 为重复数。再冒泡排序处理
  • 结果:

    [1,2]
    [{str: 1, num: 4}
    ,{str: 2, num: 2}]

去除数组中重复的数

var arr = [1, 3, 5, 2, 4, 1, 2];
  console.log(arr);
  var repeatarr = findRepeat(arr);
  var newArr = clearRepeat(arr);
  console.log('去掉重复数字之后 =》' + newArr);
  console.log('重复数字 =》' + repeatarr);
  function clearRepeat(arr) {
    var arr2 = [];
    for (var i = 0; i < arr.length; i++) {
      if (arr2.indexOf(arr[i]) == -1) {
        arr2.push(arr[i]);
      }
    }
    return arr2;
  }
  // 找出重复的数
  function findRepeat(arr) {
    var repeatarr = [];
    for (var i = 0; i < arr.length; i++) {
      for (var j = 0; j < i; j++) {
        if (arr[i] == arr[j]) {
          repeatarr.push(arr[i]);
        }
      }
    }
    return repeatarr;
  }
  • 结果:
    [1, 3, 5, 2, 4, 1, 2]
    去掉重复数字之后 =》1,3,5,2,4
    重复数字 =》1,2

冒泡排序

  var arr = [1, 3, 5, 2, 4];
  var newArr = arrSort(arr);
  console.log(newArr);
  function arrSort(arr) {
    for(var i = 0;i<arr.length;i++){
      for(var j=0;j<arr.length;j++){
        var arrEl;
        if(arr[j]<arr[j+1]){
          arrEl = arr[j+1];
          arr[j+1] = arr[j];
          arr[j] = arrEl;
        }
      }
    }
    return arr;
  }
  • 结果:
    [5, 4, 3, 2, 1]

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转载自blog.csdn.net/qq_30856231/article/details/82181370