时间复杂度(O( n^k)),思想,DFS 深度遍历
class Solution {
public:
vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
vector<vector <int > >vecvec;
if(candidates.size()==0)return vecvec;
vector<int> vec;
sort(candidates.begin(), candidates.end());
combination(candidates,0,0,target,vec,vecvec);
return vecvec;
}
void combination(vector<int>& candidates,int index,int sum,int target,vector<int> recVec,
vector<vector<int > > &vecvec){
if(sum==target) vecvec.push_back(recVec);
else if(sum<target&&index<candidates.size())
for(int k=index;k<candidates.size();++k){
if(k>index&&candidates[k]==candidates[k-1])continue;
if(sum+candidates[k]<=target) {
recVec.push_back(candidates[k]);
combination(candidates,k+1,sum+candidates[k],target,recVec,vecvec);
recVec.pop_back();
}
else return ;
}
}
};