A题，C题不讲，基础题（但是我要抨击一下这次比赛，卡cin,cout，卡的太狠了，根本就不让过的那种，QAQ）
链接：https://www.nowcoder.com/acm/contest/157/B
来源：牛客网
凤 凰
时间限制：C/C++ 1秒，其他语言2秒
空间限制：C/C++ 262144K，其他语言524288K
64bit IO Format: %lld
空间限制：C/C++ 262144K，其他语言524288K
64bit IO Format: %lld
题目描述
凤凰于飞，翙翙其羽，亦集爰止。
——《诗经·卷阿》
传说，凤凰是百鸟之王。有一天，凤凰要召开百鸟大会，百鸟国是一个由n个节点组成的树，每个节点有一只鸟，开会的节点定在1号节点。每只鸟可以花费1s通过一条边，由于每根树枝(边)的载重有限，只允许一只鸟同时通过。作为会议的策划师，HtBest想知道百鸟国的所有鸟在1点集合最少需要多少秒。
输入描述:
第一行有一个正整数n，表示百鸟国节点个数。i
接下来n-1行，第i行两个正整数a
,bi
用空格隔开，表示树上节点ai
,bi
之间有一条边。
输出描述:
第一行一个整数，表示集合最少需要的时间。
备注:
对于100%的测试数据：
1 ≤ n ≤ 1000000
数据量较大，注意使用更快的输入输出方式。
解析：有人是用搜索过的，我的第一想法就是并查集了（收获了并查集大佬的写法，也是蛮开心的，然后要注意的就是不要连接与起点有关的任何点）
，这样对于任何分枝就都能连接起来，起到+1的作用，
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链接：https://www.nowcoder.com/acm/contest/157/D
来源：牛客网
插排树
时间限制：C/C++ 1秒，其他语言2秒
空间限制：C/C++ 32768K，其他语言65536K
64bit IO Format: %lld
空间限制：C/C++ 32768K，其他语言65536K
64bit IO Format: %lld
题目描述
一年一度的山东省oi夏令营又开始了，每到这个季节，山东的oier们都会欢聚这里，一起学（tuí）习（feì）。当然，为了能更加愉快地学（tuí）习（feì），就少不了要自带电脑，用电便开始成了一种问题，于是便有一种神奇的数据结构诞生了！这就是山东省oi专用数据结构——插排树（如图）
小K为了能更好的学（tuí）习（feì），所以他想尽量的往后做，所以现在请你帮帮他，他最远可以离讲台多远。
已知插排树的根节点在讲台上，有且仅有一个根节点（根节点入度为0），最远距离即所有插排的长度，小K电脑线的长度忽略不计
本题良心大样例下载地址： https://kench.co/tree.zip
输入描述:
第一行一个整数n表示有n个节点
然后n-1行，每行三个整数a,b,c，表示插排a是接在插排b上的，插排a的长度为c
输出描述:
一个整数n表示最远距离
备注:
对于30%的数据 n<233
对于70%的数据 n<2333
对于100%的数据 n<50000
c小于20
a,b小于等于n
解析：对于每个点，暴力搜索一下，每次保留最大值
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JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 55555 94 #define MOD 1000000007 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 /*******************************************************************************************************************************************************/ 102 vector<Author> VP[MAX]; 103 int dis[MAX], ans; 104 105 void DFS(int index, int sum){ 106 int len = VP[index].size(); 107 108 ans = max(ans, sum); 109 FFI(0, len)DFS(VP[index][i].first, sum + VP[index][i].second); 110 111 } 112 int main(void){ 113 #ifdef Empirefree 114 freopen("in.txt", "r", stdin); 115 freopen("out.txt", "w", stdout); 116 #endif 117 118 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 119 int n, a, b, c; 120 121 SC(n);ME(dis, 0);ans = 0; 122 FFI(1, n){ 123 SCCC(a, b, c); 124 //b插在a上，且从b开始搜索 125 VP[b].push_back(make_pair(a, c)); 126 dis[a] = 1; 127 } 128 FFI(1, n + 1)if(!dis[i])DFS(i, 0); 129 PR(ans); 130 131 return EXIT_SUCCESS; 132 }
链接：https://www.nowcoder.com/acm/contest/157/E
来源：牛客网
青蛙
时间限制：C/C++ 1秒，其他语言2秒
空间限制：C/C++ 32768K，其他语言65536K
64bit IO Format: %lld
空间限制：C/C++ 32768K，其他语言65536K
64bit IO Format: %lld
题目描述
有一只可爱的老青蛙，在路的另一端发现了一个黑的东西，想过去一探究竟。于是便开始踏上了旅途
一直这个小路上有很多的隧道，从隧道的a进入，会从b出来，但是隧道不可以反向走。
这只青蛙因为太老了，所以很懒，现在想请你帮帮慢，问他最少需要几步才可以到达对面。
将小径看作一条数轴，青蛙初始在0上，这只青蛙可以向前跳也可以向后跳，但每次只能跳一格，每跳一格记作一步，从隧道进到隧道出算做一步。
输入描述:
第一行两个数m,n；表示黑色物品在数轴m点上，数轴上总共有n个隧道
接下来n行，每行a，b两个数，表示从a进会从b出
10 <= m,n <= 233
0<a,b<=m
输出描述:
一个数ans表示最小步数
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JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 234 94 #define MOD 1000000007 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 vector<pair<string, int> > VP; 102 103 /*******************************************************************************************************************************************************/ 104 //类似一维上的传送门题 105 int vis[MAX]; 106 int dis[MAX]; 107 int n; 108 int dir[2] = {-1, 1}; 109 struct Node{ 110 int x, time; 111 bool operator < (const Node& a)const{return time > a.time;} 112 }bn, en, temp1, temp2, cnt; 113 114 115 int BFS(){ 116 priority_queue<Node> q;ME(dis, 0); 117 dis[0] = 1;q.push(bn); 118 119 while(!q.empty()){ 120 temp1= q.top();q.pop(); 121 if(temp1.x == en.x) return temp1.time; 122 FFI(0, 2){ 123 temp2.x = temp1.x + dir[i]; 124 temp2.time = temp1.time + 1; 125 if(temp2.x >= 0 && temp2.x <= n && !dis[temp2.x]){ 126 dis[temp2.x] = 1; 127 q.push(temp2); 128 } 129 } 130 if(vis[temp1.x]){ 131 cnt.x = vis[temp1.x]; 132 cnt.time = temp1.time + 1; 133 if(cnt.x >= 0 && cnt.x <= n && !dis[cnt.x]) q.push(cnt); 134 } 135 } 136 return 0; 137 } 138 int main(void){ 139 #ifdef Empirefree 140 freopen("in.txt", "r", stdin); 141 freopen("out.txt", "w", stdout); 142 #endif 143 144 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 145 int m, a, b; 146 cin>>n>>m;ME(vis, 0); 147 FFI(0, m){ 148 cin>>a>>b; 149 vis[a] = b; 150 } 151 bn.x = 0;bn.time = 0;en.x = n; 152 153 cout<<BFS()<<endl; 154 return EXIT_SUCCESS; 155 }
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JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 234 94 #define MOD 1000000007 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 vector<pair<string, int> > VP; 102 103 /*******************************************************************************************************************************************************/ 104 vector<int> vec[MAX]; 105 int dis[MAX], n; 106 void DFS(int index, int sum){ 107 int len; 108 109 dis[index] = sum; 110 len = vec[index].size(); 111 if(index <= n && dis[index + 1] > sum + 1)DFS(index + 1, sum + 1); 112 if(index - 1 >= 0 && dis[index - 1] > sum + 1)DFS(index - 1, sum + 1); 113 FFI(0, len)if(dis[vec[index][i]] > sum + 1)DFS(vec[index][i], sum + 1); 114 } 115 int main(void){ 116 #ifdef Empirefree 117 freopen("in.txt", "r", stdin); 118 freopen("out.txt", "w", stdout); 119 #endif 120 121 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 122 int m, a, b; 123 124 cin>>n>>m;ME(dis, INF); 125 FFI(0, m){ 126 cin>>a>>b; 127 vec[a].push_back(b); 128 } 129 130 DFS(0, 0); 131 cout<<dis[n]<<endl; 132 return EXIT_SUCCESS; 133 }
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KL::JGBBBgE6Hp6XMQ; . ... ,2s ,,,,:::::,:::::::,,.:sQQB2 ;DHa5U52S2U25USJ 45 a: :7;1BB2 .v, sL;LPQgDBPH6KPQBpGBG . ... .. aP:. .. ,::,:::::,,,,.;rSgBQDa; :gSSwSUUU525US2U 46 5; ;;r2QBB, .s: :a7:PBZ2,:BEaZPKgBZOgB, . ...:LEHri::,:.,,.,,,::rsXRBgGKEJi, 2GH252SUS5S11wH5 47 U: ;:rwDBBr .c, rB6r 167.,,RQPpEP6OpKEBc ., . : ::sS7;cKB6HHa1XOQRRQBRgEZDBH; .. ;RZUPSSU525USSpK2 48 s; ;::aBg, .; .Gv,H::,,::,;BQDOGHPXpKBs .,. . .,. .r:;:6gOEBQRRRDggQgOHgMGL, .;PEHHXaaKaPXPKPaXS 49 s7.:,sBa :..S, vE::::; 7BBMgZH6pQBr . ,:, ,.,r2RHSSpMZPKRRZpgggav, ;UpEZaaaKHHUHPPaUJHGO 50 a;.775: .::rU. gR:,:. :;:BBBBQar . ,, ,.,7rggJwU6DDGMgOGgXc:, ,rPGOpKSXSXSKUKHU1UHgOEP 51 1i :SZJrLXpBBMRB: .v Ba,. :sv: . irsBUSpEEGPPpg65r:..,;sKZDZHSX5XaHU55K2wUGMRZ6Z6 52 :K :7asvwc2MgEQB, :gg.:iB7 .,,,:. ...,. . .. .:iM6GEpSSXZOEs:...;spZpKKXXSX5Xa5Ja5wwKGQDEpp6OZ 53 w; ,LXLr77sLwL5aR. gRgQgaQBi ,vJwvi,. .;;:;7: . . ,... rRDRJUSXpgas:,.:;U66SaHa2X5aUa552X12SgQgpZpEpGOD 54 H: ;XJ;77rv7rJUaQ;rgaPgXXHBB; . . .ri:;; ,: . :6QZEKHXpXXL:,::r1PKXaa2XSS5a5S5UJ22aOBgEpOppZOOgG 55 iwsJsr7rsLrrLcJ2gQGXHwa1SUHBB: . ... . .., : 1BRKpOEGp2Jr;::rsXP1Uaa2U5a5aUa5SsSpgQRZGZEEZZOOgDg 56 ,cs5aXaP552ssLwRSHXaSS5asXBB. . . . LBBgGgZHsr;vrr;rcXpP5UUS5X5S2XS5SS1URBggpEZgDDGOGggRD 57 ,;irrs2KgQRPJJJSUXKXSHJpBM . . . ZBBOUsr;:. ,,,rHgZPUaSaUSUSSXaUPXsSBB6ZZp6EEGOOGDEggO 58 ;BBQQZaSJ5J15SJDQ7 .iEBL:. . .,:,:;SRQGZXPXXSHaS2UUSUSswQB6OZgG6pZZGODEOGDE 59 JgUri1aGEpEpXSS5LBQ, .rLap2Jr ;712OO6ZggRDZXHXpKK2211LLLc7wgBa2PODRGE6OZgDgGDGD 60 7QB; ,Jc76DaZXOZgDPEBBX, :c1HEZ1c;:,.,:;cHDgQQggMZgGOZO6OEGpXsLLsJXHPOBBBc;vss5EMggZDODOgED6 61 LZJ::iwrrr72EPgXU5OBBBBBBBp7: .i5P6wL;, .:LS6DMgMgZKgEOPOGGDDGEXULvLSOBBBBBQBgDQDJ5rrr7JOQQDDZGEgDD 62 wp rR5, .HQRX7r72RQBBBBBQBMEK6Uc7sc7cHOU:, .:LHgOQg6ZOPZpZGGEDERZPwcr7LKDDaJr:. rBX;;:r:ir1DBQMgRgDp 63 7D,sw: , Z. .LgBBQBBOsJaQBBBBBBXrr. .:rwZBBQgROgDgDOERRMgROOScrLsPP5r, 7Qs,::::::rUgRgZOG6 64 ,Q57:r ,: ,r U: .;; .vL7L;r:UG7.:sr;JSgQBgDEZXXUSXpHa21svr7r7s2v:. iQK...:,:::;LLJJws 65 OBHs;. :;;,v H: :6X; rpL;7pSrrr7r;::,....,,:;iirrvvvr, :BBPs;;:,,,,::;:: 66 ::rPDEL:..7:c;7r pK .: :KL.:r:.. ..:icsS5sr:,. JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define SCCCC(a, b, c, d) scanf("%d%d%d%d", &a, &b, &c, &d) 91 #define PR(x) printf("%d\n", x) 92 #define PRR(a, b) printf("%d%d\n", a, b); 93 #define INF 0x3f3f3f3f 94 #define MAX 333 95 #define MOD 1000000007 96 #define E 2.71828182845 97 #define M 8 98 #define N 6 99 typedef long long LL; 100 const double PI = acos(-1.0); 101 typedef pair<int, int> Author; 102 vector<pair<string, int> > VP; 103 104 /*******************************************************************************************************************************************************/ 105 int dis[MAX][MAX];char matrix[MAX][MAX]; 106 struct Node{ 107 int x; 108 int y; 109 int time; 110 }bn, en, temp1, temp2; 111 vector<Node> vec[MAX][MAX]; 112 int n, m, q; 113 bool Check(int x, int y){ 114 if(x >= 0 && x < n && y >= 0 && y < m && matrix[x][y] != '#') return true; 115 else return false; 116 } 117 void DFS(int x,int y, int sum){ 118 int len; 119 120 dis[x][y] = sum; 121 if(Check(x + 1, y) && dis[x + 1][y] > sum + 1) DFS(x + 1, y, sum + 1); 122 if(Check(x - 1, y) && dis[x - 1][y] > sum + 1) DFS(x - 1, y, sum + 1); 123 if(Check(x, y + 1) && dis[x][y + 1] > sum + 1) DFS(x, y + 1, sum + 1); 124 if(Check(x, y - 1) && dis[x][y - 1] > sum + 1) DFS(x, y - 1, sum + 1); 125 len = vec[x][y].size(); 126 FFI(0, len){ 127 if(Check(vec[x][y][i].x, vec[x][y][i].y) && dis[vec[x][y][i].x][vec[x][y][i].y] > sum + 3) 128 DFS(vec[x][y][i].x, vec[x][y][i].y, sum + 3); 129 } 130 } 131 void Clear(){ 132 133 FFI(0, n) 134 FFJ(0, m) 135 vec[i][j].clear(); 136 } 137 int main(void){ 138 #ifdef Empirefree 139 freopen("in.txt", "r", stdin); 140 freopen("out.txt", "w", stdout); 141 #endif 142 143 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 144 int a, b, c, d; 145 146 while(SCCC(n, m, q)){ 147 ME(dis, INF);Clear(); 148 FFI(0, n){ 149 150 scanf("%s", matrix[i]); 151 FFJ(0, m){ 152 if(matrix[i][j] == 'S') bn.x = i,bn.y = j; 153 if(matrix[i][j] == 'T') en.x = i,en.y = j; 154 } 155 } 156 FFI(0, q){ 157 SCCCC(a, b, c, d); 158 temp1.x = c;temp1.y = d; 159 vec[a][b].push_back(temp1); 160 } 161 DFS(bn.x, bn.y, 0); 162 if(dis[en.x][en.y] == INF) PR(-1); 163 else PR(dis[en.x][en.y]); 164 } 165 return EXIT_SUCCESS; 166 }
链接：https://www.nowcoder.com/acm/contest/157/F
来源：牛客网
三轮
时间限制：C/C++ 1秒，其他语言2秒
空间限制：C/C++ 262144K，其他语言524288K
64bit IO Format: %lld
空间限制：C/C++ 262144K，其他语言524288K
64bit IO Format: %lld
题目描述
解析：完全背包，QAQ
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JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 52000 94 #define MOD 19260817 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 vector<pair<string, int> > VP; 102 int read() 103 { 104 int x=0,f=1; char ch; 105 while (ch=getchar(),ch<'0'||ch>'9') if (ch=='-') f=-1; 106 while (x=x*10+ch-'0',ch=getchar(),ch>='0'&&ch<='9'); 107 return x*f; 108 } 109 /*******************************************************************************************************************************************************/ 110 LL bag[MAX]; 111 int main(void){ 112 #ifdef Empirefree 113 freopen("in.txt", "r", stdin); 114 freopen("out.txt", "w", stdout); 115 #endif 116 117 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 118 LL n, m, a, ans; 119 120 bag[0] = 1;ans = 0; 121 n = read(); m = read(); 122 FFI(0, n){ 123 a = read(); 124 FFJ(a, m + 1) 125 bag[j] = (bag[j] + bag[j - a]) % MOD; 126 } 127 FFI(1, m + 1) ans = (ans + bag[i]) % MOD; 128 printf("%lld\n", ans); 129 130 return EXIT_SUCCESS; 131 }