LeetCode144. 二叉树的前序遍历

二叉树的前序遍历主要有两种方法实现:

1.递归实现:

class Solution {
public:
    vector<int> preorderTraversal(TreeNode* root) {
        vector<int> ans;
        preorder(ans,root);
        return ans;
    }
    
    void preorder(vector<int>& ans,TreeNode* root){
        if(root==NULL)
            return;
        ans.push_back(root->val);
        preorder(ans,root->left);
        preorder(ans,root->right);
    }
};

2.非递归实现:

class Solution {
public:
    vector<int> preorderTraversal(TreeNode* root) {
        vector<int> ans;
        if(root==NULL)
            return ans;
        preorder(ans,root);
        return ans;
    }
    
    void preorder(vector<int>& ans,TreeNode* root){
        stack<TreeNode*> s;
        while(!s.empty() || root!=NULL){
            while(root!=NULL){
                ans.push_back(root->val);
                s.push(root);
                root = root->left;
            }
            if(!s.empty()){
                root = s.top();
                s.pop();
                root = root->right;
            }
        }
    }
};

简单说一下思路:当根节点不为空时,访问根节点,并入栈;若根节点的左子树不为空,则将左结点置为根节点;若为空,则取栈顶元素,并将栈顶元素的右节点置为根节点,一直到栈为空并且root为空。

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转载自blog.csdn.net/Jaster_wisdom/article/details/81333426