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题目描述
给定一个二叉树,返回它的 前序 遍历。
示例:
输入: [1,null,2,3]
1
\
2
/
3
输出: [1,2,3]
进阶: 递归算法很简单,你可以通过迭代算法完成吗?
递归代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> result;
vector<int> preorderTraversal(TreeNode* root) {
if(root){
result.push_back(root->val);
preorderTraversal(root->left);
preorderTraversal(root->right);
}
return result;
}
};
非递归代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int> res;
stack<TreeNode*> s;
//TreeNode *p=root;
while(root||!s.empty()){
if(root){
s.push(root);
res.push_back(root->val);
root=root->left;
}
else{
root=s.top();
s.pop();
root=root->right;
}
}
return res;
}
};