JavaScript 18位身份证验证及身份证号码规则

<script>
  function checkID(ID) {
    if(typeof ID !== 'string') return '非法字符串';
    var city = {11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江 ",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北 ",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏 ",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"};
    var birthday = ID.substr(6, 4) + '/' + Number(ID.substr(10, 2)) + '/' + Number(ID.substr(12, 2));
    var d = new Date(birthday);
    var newBirthday = d.getFullYear() + '/' + Number(d.getMonth() + 1) + '/' + Number(d.getDate());
    var currentTime = new Date().getTime();
    var time = d.getTime();
    var arrInt = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2];
    var arrCh = ['1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'];
    var sum = 0, i, residue;
 
    if(!/^\d{17}(\d|x)$/i.test(ID)) return '非法身份证';
    if(city[ID.substr(0,2)] === undefined) return "非法地区";
    if(time >= currentTime || birthday !== newBirthday) return '非法生日';
    for(i=0; i<17; i++) {
      sum += ID.substr(i, 1) * arrInt[i];
    }
    residue = arrCh[sum % 11];
    if (residue !== ID.substr(17, 1)) return '非法身份证哦';
 
    return city[ID.substr(0,2)]+","+birthday+","+(ID.substr(16,1)%2?" 男":"女")
  }
</script>

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转载自zyazyz008.iteye.com/blog/2396814
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