[luogu1801] 黑匣子_NOI导刊2010提高(06)

传送门
照理来说很久很久以前就做过这个题(并且做过很多很多遍),但是从来没有写过…
于是趁这个机会学了Treap(好吧感觉就是对着蓝书抄了一遍不知道记住了多少),发现Treap比我想象中简单好多。然后正解是对顶堆吧。用优先队列不开O2和Treap根本没差多少啊0 0

Treap版
那个root[2]是最开始开了2e5的数组发现其实只用了root[1]

#include<bits/stdc++.h>
using namespace std;
const int N=200002;
int n,m,a[N],u[N];
struct node{
    int r,v,s;
    node *ch[2];

    int cmp(int x){ return x>v; }

    node(int v):v(v) { ch[0]=ch[1]=NULL;r=rand();s=1; }

    void maintain(){
        s=1;
        if (ch[0]!=NULL) s+=ch[0]->s;
        if (ch[1]!=NULL) s+=ch[1]->s;
    }
};
node* root[2];

void read(int &x){
    char ch=getchar();x=0;int w=1;
    for(;ch<'0'||ch>'9';ch=getchar()) if (ch=='-') w=-1;
    for(;ch>='0'&&ch<='9';ch=getchar()) x=(x<<3)+(x<<1)+ch-'0';
    x*=w;
}

void rorate(node* &o,int d){
    node* k=o->ch[d^1];o->ch[d^1]=k->ch[d];k->ch[d]=o;
    o->maintain();k->maintain();o=k;
}

void add(int x,node* &o){
    if (o==NULL) o=new node(x);
     else{
        int d=o->cmp(x);
        add(x,o->ch[d]);
        if (o->ch[d]->r>o->r) rorate(o,d^1);
     }
    o->maintain();
}

int get(node* &o,int k){
//  if (o==NULL) return 0;
    int s=(o->ch[0]==NULL?0:o->ch[0]->s);
    if (k==s+1) return o->v;
     else if (k<=s) return get(o->ch[0],k);
      else return get(o->ch[1],k-s-1);
}

int main(){
    freopen("1.in","r",stdin);
    freopen("1.out","w",stdout);
    read(n);read(m);
    for(int i=1;i<=n;i++) read(a[i]);
    for(int i=1;i<=m;i++) read(u[i]);
    int j=1;
    for(int i=1;i<=n;i++){
        add(a[i],root[1]);
        for(;u[j]==i;cout<<get(root[1],j)<<endl,j++);
    } 
    return 0;
}

然后是堆

#include<bits/stdc++.h>
using namespace std;
const int N=200002;
int n,m,a[N],u[N];
priority_queue<int> h1;
priority_queue<int,vector<int>,greater<int> > h2;

void read(int &x){
    char ch=getchar();x=0;int w=1;
    for(;ch<'0'||ch>'9';ch=getchar()) if (ch=='-') w=-1;
    for(;ch>='0'&&ch<='9';ch=getchar()) x=(x<<3)+(x<<1)+ch-'0';
    x*=w;
}

int main(){
    freopen("1.in","r",stdin);
    freopen("1.out","w",stdout);
    read(n);read(m);
    for(int i=1;i<=n;i++) read(a[i]);
    for(int i=1;i<=m;i++) read(u[i]);
    int j=1;h1.push(-2e9-1);
    for(int i=1;i<=n;i++){
        if (a[i]<h1.top()) h2.push(h1.top()),h1.pop(),h1.push(a[i]);
         else h2.push(a[i]);
        for(;u[j]==i;j++){
            int x=h2.top();
            cout<<x<<endl;
            h1.push(x);h2.pop();
        }
    }
    return 0;
}

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转载自blog.csdn.net/ymzqwq/article/details/79988060