web4

按提示查看源代码

<html>
<title>BKCTF-WEB4</title>
<body>
<div style="display:none;"></div>
<form action="index.php" method="post" >
看看源代码?<br>
<br>
<script>
var p1 = '%66%75%6e%63%74%69%6f%6e%20%63%68%65%63%6b%53%75%62%6d%69%74%28%29%7b%76%61%72%20%61%3d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%70%61%73%73%77%6f%72%64%22%29%3b%69%66%28%22%75%6e%64%65%66%69%6e%65%64%22%21%3d%74%79%70%65%6f%66%20%61%29%7b%69%66%28%22%36%37%64%37%30%39%62%32%62';
var p2 = '%61%61%36%34%38%63%66%36%65%38%37%61%37%31%31%34%66%31%22%3d%3d%61%2e%76%61%6c%75%65%29%72%65%74%75%72%6e%21%30%3b%61%6c%65%72%74%28%22%45%72%72%6f%72%22%29%3b%61%2e%66%6f%63%75%73%28%29%3b%72%65%74%75%72%6e%21%31%7d%7d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%6c%65%76%65%6c%51%75%65%73%74%22%29%2e%6f%6e%73%75%62%6d%69%74%3d%63%68%65%63%6b%53%75%62%6d%69%74%3b';
eval(unescape(p1) + unescape('%35%34%61%61%32' + p2));
</script>

<input type="input" name="flag" id="flag" /> 
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>

将p1和p2,“%35%34%61%61%32”进行URL解码或者十六进制转换ASCII(不过需要先去除%)

按照eval()函数进行组合可以得到一个字符串"67d709b2b54aa2aa648cf6e87a7114f1"

function checkSubmit(){
	var a=document.getElementById("password");
	if("undefined"!=typeof a){
		if("67d709b2b54aa2aa648cf6e87a7114f1"==a.value)
			return!0;
		alert("Error");
		a.focus();
		return!1
	}
}
document.getElementById("levelQuest").onsubmit=checkSubmit;

提交该字符串即可获得flag

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转载自blog.csdn.net/tc125/article/details/81100722
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