Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 556225 Accepted Submission(s): 140960
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
Author
DOOM III
Recommend
We have carefully selected several similar problems for you: 1002 1090 1003 1091 1004
心得：注意格式
扫描二维码关注公众号，回复：
2392316 查看本文章
#include<bits/stdc++.h>
using namespace std;
int main(void)
{
int n,i;
while(~scanf("%d",&n))
{
int sum=0;
for(i=1;i<=n;i++)
sum+=i;
printf("%d\n\n",sum);
}
return 0;
}