二叉树:前序,中序,后序,非递归调用C++实现

struct TreeNode
{
    int val;
    TreeNode* left;
    TreeNode* right;
    TreeNode(int x):val(x),left(NULL),right(NULL){}

};


    void preorder_print1(TreeNode* root) //非递归调用 前序
    {
        if(!root) return ;
        stack<TreeNode*> temp;

        while(root || !temp.empty())
        {
            if(root)
            {
                cout<<root->val<<" ";
                temp.push(root);
                root=root->left;
            }else
            {
                TreeNode* node=temp.top();
                temp.pop();
                root=node->right;
            }

        }
        cout<<endl;
    }

    void zhongxu_print1(TreeNode* root)   // 非递归调用 中序
    {
        if(!root) return ;
        stack<TreeNode*> temp;
        while(root || !temp.empty())
        {
            while(root)
            {
                temp.push(root);
                root=root->left;
            }
            TreeNode* node=temp.top();
            cout<<node->val<<" ";
            temp.pop();
            root=node->right;
        }
        cout<<endl;
    }
    void houxu_print1(TreeNode* root)  // 非递归调用 后序
    {
        if(!root) return ;
        stack<TreeNode*> temp;
        TreeNode* pre;
        temp.push(root);
        while(!temp.empty())
        {
            TreeNode* curr=temp.top();
            if((!curr->left && !curr->right) || (pre && (curr->left==pre || curr->right==pre)))
            {
                cout<<curr->val<<" ";
                temp.pop();
                pre=curr;
            }else
            {
                if(curr->right)
                {
                    temp.push(curr->right);
                }
                if(curr->left)
                {
                    temp.push(curr->left);
                }

            }
        }
        cout<<endl;
    }

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转载自blog.csdn.net/csu_guo_liang/article/details/80904745