简单的通过shell脚本接收参数进行数据库操作

建表sql语句:


SET FOREIGN_KEY_CHECKS=0;

-- ----------------------------
-- Table structure for `cent_survival`
-- ----------------------------
DROP TABLE IF EXISTS `cent_survival`;
CREATE TABLE `cent_survival` (
  `centCode` varchar(32) NOT NULL,
  `survivalCode` char(1) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of cent_survival
-- ----------------------------
INSERT INTO `cent_survival` VALUES ('0001', '1');
INSERT INTO `cent_survival` VALUES ('0002', '1');

创建一个shell文件

 vim changeMysql.sh

修改文件权限

chmod 777 changeMysql.sh

编辑内容(以修改为例)

#!/bin/bash
read -t 30 -p "请输入中心代码【南0001/北0002】:" centCode
echo -e "\n"
read -t 30  -p "请输入中心状态码【挂机0/正常1】:" survivalCode
HOSTNAME="127.0.0.1"  #数据库信息
PORT="3306"
USERNAME="root"
PASSWORD="123456"

DBNAME="test"  #数据库名称
TABLENAME="cent_survival" #数据库中表的名称
#查询
select_sql="select * from ${TABLENAME}"
mysql -h${HOSTNAME} -P${PORT} -u${USERNAME} -p${PASSWORD} ${DBNAME} -e "${select_sql}"

#更新数据
update_sql="update ${TABLENAME} set survivalCode=${survivalCode} where centCode = ${centCode}"
mysql -h${HOSTNAME} -P${PORT} -u${USERNAME} -p${PASSWORD} ${DBNAME} -e "${update_sql}"

mysql -h${HOSTNAME} -P${PORT} -u${USERNAME} -p${PASSWORD} ${DBNAME} -e "${select_sql}"

测试:

[root@localhost local]# ./changeMysql.sh

这里写图片描述

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转载自blog.csdn.net/leisure_life/article/details/78800605
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