LeetCode41 First Missing Positive 消失的最小正数

题目描述:
Given an unsorted integer array, find the smallest missing positive integer.

Example 1:

Input: [1,2,0]
Output: 3

Example 2:

Input: [3,4,-1,1]
Output: 2

Example 3:

Input: [7,8,9,11,12]
Output: 1

Note:

Your algorithm should run in O(n) time and uses constant extra space.
题源:here;完整实现:here

思路:
我们从1开始排,对于长度为n的输入来讲,最多占据n个位置,所以,我们用一个数组来记录从1到n是否填上;然后遍历这个数组,没有被填上的位置就是消失的位置,如果1-n个位置都被填上的话,就输出n+1,代码如下:

class Solution {
public:
    int firstMissingPositive(vector<int>& nums) {
        if(nums.size() == 0) return 1;
        vector<bool> records(nums.size(), false);
        for(int i = 0;i<nums.size();i++){
            if(nums[i]<=0 || nums[i]>nums.size()) continue;
            else records[nums[i]-1] = true;
        }
        for(int i = 0;i<nums.size();i++){
            if(records[i]) continue;
            else return i+1;
        }

        return nums.size()+1;
    }
};

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转载自blog.csdn.net/m0_37518259/article/details/80807089