深搜遍历每个节点,记录数字即可
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumNumbers(self, root: TreeNode) -> int:
self.ans = 0
def dfs(root, num):
if not root:
return
if not root.left and not root.right:
self.ans += num*10 + root.val
return
dfs(root.left, num*10 + root.val)
dfs(root.right, num*10 + root.val)
dfs(root, 0)
return self.ans