P1088 火星人(全排列,DFS+时间复杂度压缩)

import java.util.Scanner;

public class P1088 {
	static int N,M,T;
	static int[] a;
	static boolean[] flag;
	static boolean[] isVisited;//是否找到结果标记
	static StringBuilder sb = new StringBuilder();
	public static void main(String[] args) throws Exception {
		Scanner sc = new Scanner(System.in);
		N = sc.nextInt();
		M = sc.nextInt()+1;
		a = new int[N+1];
		flag = new boolean[N+1];
		isVisited = new boolean[N+1];
		
		for(int i=1;i<=N;i++) {
			a[i] = sc.nextInt();
		}
		dfs(1);
		for(int i=1;i<=N;i++) {
			System.out.print(a[i]+" ");
		}
	}
	private static void dfs(int pos) throws Exception {
		if(pos>=N+1) {
			M--;
			if(M==0) {
				return;
			}
			return;
		}
		
		for(int i=(isVisited[pos]?1:a[pos]);i<=N;i++) {
			if(flag[i]==false) {
				flag[i] = true;
				a[pos] = i;
				dfs(pos+1);
				if(M==0) {
					return;
				}
				flag[i] = false;
			}
		}
		isVisited[pos] = true;
		return;
	}
}

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转载自blog.csdn.net/qq_28635317/article/details/114846882
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