UVA - 10048(floyd)

题目:Path and Wall

或者在vjudge上:Path and Wall

分析:floyd即可,DFS找最短会TLE
#include <iostream>
#include<cstring>
#include<vector>
#include<stdio.h>
#include<queue>
#include<math.h>
#include<stack>
#include<math.h>
#include<algorithm>
#include<map>
#include<set>
#include<iostream>
using namespace std;
#define MAX 0x3f3f3f3f
typedef long long ll;
int n,m,k;
int road[105][105];
void floyd()
{
    
    
    for(int k = 1; k <= n ;k++)
    {
    
    
        for(int i = 1; i <= n; i++)
        {
    
    
            for(int j = 1; j <= n ;j++)
            {
    
    
                int mmax = max(road[i][k], road[k][j]);
                if(mmax < road[i][j])
                    road[i][j] = mmax;
            }
        }
    }
}
int main()
{
    
    
    int t = 1;
    while(1)
    {
    
    
        cin>>n>>m>>k;
        if(n==0&&m==0&&k==0)
            break;
        memset(road,MAX,sizeof(road));
        if(t != 1)
            cout<<endl;
        while(m--)
        {
    
    
            int a,b,c;
            cin>>a>>b>>c;
            road[a][b] = road[b][a] = c;
        }
        floyd();
        cout<<"Case #"<<t<<endl;
        while(k--)
        {
    
    
            int a,b;
            cin>>a>>b;
            if(road[a][b] == MAX)
                cout<<"no path\n";
            else
                cout<<road[a][b]<<endl;
        }
        t++;
    }
    return 0;
}

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转载自blog.csdn.net/qq_43567222/article/details/114581337