题目描述
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + … + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
思路
题意就是,从 1 到 n 累加求和,输出和。注意输出的格式。
C++代码:
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
while(cin >> n)
{
long long sum = 0;
for(int i = 0; i <= n; i++)
sum += i;
cout << sum << endl << endl;
}
return 0;
}