http://acm.hdu.edu.cn/showproblem.php?pid=1001
Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
Code in C
#include <stdio.h>
int main(){
int n,i,sum=0;
while(scanf("%d", &n)!=EOF){
for(i=1;i<=n;i++){
sum += i;
}
printf("%d\n\n", sum);
sum=0;
}
return 0;
}
反思
while(scanf("%d", &n)!=EOF)
于我来说,做题的时候没有想到这行代码
解释一下:不断地读取n,直到文件末尾
猜想:这网站测试代码用的测试用例是保存在文件中的?