Codeforces 1353D Constructing the Array

题目链接:

https://codeforces.com/contest/1353/problem/D

思路:

我们将所有待处理的子线段按照{长度,左端点序号,右端点序号}按序存储在优先队列中,然后挨个处理即可;

代码:

#include<bits/stdc++.h>

using namespace std;

struct seg {
    
    
	int len, l, r;
	bool operator < (const seg & s) const {
    
    
		return len == s.len ? s.l < l : s.len > len;
	}
};
void solve(int & n) {
    
    
	priority_queue<seg> que;
	que.push(seg{
    
    n, 1, n});
	vector<int> ans(n + 1);
	int cnt = 1;
	while(!que.empty()) {
    
    
		seg s = que.top();
		que.pop();
		int mid = s.l + s.r;
		if(mid & 1) mid = (mid - 1) >> 1;
		else mid >>= 1;
		ans[mid] = cnt++;
		if(mid - 1 >= s.l) que.push(seg{
    
    mid - s.l, s.l, mid - 1});
		if(s.r >= mid + 1) que.push(seg{
    
    s.r - mid, mid + 1, s.r});
	}
	for(int i = 1; i <= n; i++) printf("%d ", ans[i]);
	putchar('\n');
}

int main() {
    
    
#ifdef MyTest
	freopen("Sakura.txt", "r", stdin);
#endif
	int kase;
	scanf("%d", &kase);
	while(kase--) {
    
    
		int n;
		scanf("%d", &n);
		solve(n);
	}	
	return 0;	
}

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转载自blog.csdn.net/qq_45228537/article/details/106157905
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