sdnuoj 1020.简单表达式计算

switch语句的运用

#include <cstdio>
#include <cstring>
#include <string>
#include <cmath>
#include <iostream>
#include <algorithm>
#include <vector>
#include <stack>
#include <queue>
#include <stdlib.h>
#include <sstream>
#include <map>
#include <set>
typedef long long ll;
using namespace std;
int ar[10005];
int main()
{
    
    
   int n, m, sum;
   char c;
   scanf("%d%c%d",&n,&c,&m);
   switch (c)
   {
    
    
       case '+': printf("%d",n+m);break;//记得每一句后面都要break
       case '-': printf("%d",n-m);break;
       case '*': printf("%d",n*m);break;
       case '/': printf("%d",n/m);break;
   }
   return 0;
}