PAT甲级1011 World Cup Betting (20分)
题目:
题目分析:很简单,n2复杂度
AC代码:
#include <cstdio>
using namespace std;
int main() {
char c[3] = {
'W','T','L'};
double ans = 1.0;
for(int i = 0; i < 3; i++) {
double maxvalue = 0.0;
int maxchar = 0;
for(int j = 0; j < 3; j++) {
double temp;
scanf("%lf", &temp);
if(maxvalue <= temp) {
maxvalue = temp;
maxchar = j;
}
}
ans *= maxvalue;
printf("%c ", c[maxchar]);
}
printf("%.2f", (ans * 0.65 - 1) * 2);
return 0;
}